page ,132 title strrev - reverse a string in place ;*** ;strrev.asm - reverse a string in place ; ; Copyright (c) 1985-1997, Microsoft Corporation. All rights reserved. ; ;Purpose: ; defines _strrev() - reverse a string in place (not including ; '\0' character) ; ;******************************************************************************* .xlist include cruntime.inc .list page ;*** ;char *_strrev(string) - reverse a string in place ; ;Purpose: ; Reverses the order of characters in the string. The terminating ; null character remains in place. ; ; Algorithm: ; char * ; _strrev (string) ; char *string; ; { ; char *start = string; ; char *left = string; ; char ch; ; ; while (*string++) ; ; ; string -= 2; ; while (left < string) ; { ; ch = *left; ; *left++ = *string; ; *string-- = ch; ; } ; return(start); ; } ; ; NOTE: There is a check for an empty string in the following code. ; Normally, this would fall out of the "cmp si,di" instruction in the ; loop portion of the routine. However, if the offset of the empty ; string is 0 (as it could be in large model), then the cmp does not ; catch the empty string and the routine essentially hangs (i.e., loops ; moving bytes one at a time FFFFh times). An explicit empty string ; check corrects this. ; ;Entry: ; char *string - string to reverse ; ;Exit: ; returns string - now with reversed characters ; ;Uses: ; ;Exceptions: ; ;******************************************************************************* CODESEG public _strrev _strrev proc \ uses edi esi, \ string:ptr byte mov edi,[string] ; di = string mov edx,edi ; dx=pointer to string; save return value mov esi,edi ; si=pointer to string xor eax,eax ; search value (null) or ecx,-1 ; cx = -1 repne scasb ; find null cmp ecx,-2 ; is string empty? (if offset value is 0, the je short done ; cmp below will not catch it and we'll hang). dec edi ; string is not empty, move di pointer back dec edi ; di points to last non-null byte lupe: cmp esi,edi ; see if pointers have crossed yet jae short done ; exit when pointers meet (or cross) mov ah,[esi] ; get front byte... mov al,[edi] ; and end byte mov [esi],al ; put end byte in front... mov [edi],ah ; and front byte at end inc esi ; front moves up... dec edi ; and end moves down jmp short lupe ; keep switching bytes done: mov eax,edx ; return value: string addr ret ; _cdecl return _strrev endp end